Proving the Equality of Ratios: A Mathematical Analysis

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In summary, we are asked to prove that the expression ((a^5 + b^2c^2 + a^3c^2)/(b^4c + d^4 + b^2cd^2)) ^ (1/2) is equal to a/d. To do so, we can use the fact that a/b = b/c = c/d = k, and then plug in values for k until we reach the desired expression. By simplifying, we can see that the final result is indeed equal to a/d.
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Miike012
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Homework Statement


If a/b = b/c = c/d, prove that a/d is equal to ((a^5 + b^2c^2 + a^3c^2)/(b^4c + d^4 + b^2cd^2)) ^ (1/2)


The Attempt at a Solution


Prove: ((a^5 + b^2c^2 + a^3c^2)/(b^4c + d^4 + b^2cd^2)) ^ (1/2) = a/d

Let: a/b = c/d = e/f = k -- Then: a = bk; c = dk; e = fk

((a^5 + b^2c^2 + a^3c^2)/(b^4c + d^4 + b^2cd^2)) ^ (1/2) = (( b^5k^5 + b^2d^2k^2 + b^3d^2k^5) / (b^4dk + d^4 + bd^3k)) ^(1/2)

(Should I simplify more? (( b^5k^5 + b^2d^2k^2 + b^3d^2k^5) / (b^4dk + d^4 + bd^3k)) ^(1/2) )

= a/d = bk/d ( Because k = a/b then ((b)(a/b))/d = a/d

Once again thanks for the help.
 
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Nevermind... in the (( b^5k^5 + b^2d^2k^2 + b^3d^2k^5) / (b^4dk + d^4 + bd^3k)) ^(1/2) ) would I just plug in a/b or b/c or c/d for k until I get ((a^5 + b^2c^2 + a^3c^2)/(b^4c + d^4 + b^2cd^2)) ^ (1/2)
 

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