Cross Product and Area

  • Thread starter ƒ(x)
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  • #1
ƒ(x)
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How do you prove that ||VxU|| is the area of the parallelegram they form?

I know that the cross product is a vector perpendicular to V and U
 

Answers and Replies

  • #2
ƒ(x)
328
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Nvm, found a proof.
 

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