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Mathematics
Differential Geometry
LeviCivita in Orthogonal Curvilinear Coordinate System: "Cross Product Matrix
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[QUOTE="ltkach2015, post: 5760094, member: 520445"] I am not following. I should have said: assuming that the Levi Civita 3x3x3 matrix would have to remain the same for orthogonal curvilinear coordinates. That's my own thought as I knew I had to somehow generate the same velocity vector. And I think the article confirms my thinking; I quoted it in the beginning of my post: "Levi-Civita symbol are independent of any [URL='https://en.wikipedia.org/wiki/Metric_tensor']metric tensor[/URL] and [URL='https://en.wikipedia.org/wiki/Coordinate_system']coordinate system[/URL]" But if that's the case how do I get those matrices that form the 3x3x3 for spherical coordinates? Should I use the normalized spherical unit vectors to generate that 3x3x3? As spherical is orthogonal and not orthonormal. [/QUOTE]
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Differential Geometry
LeviCivita in Orthogonal Curvilinear Coordinate System: "Cross Product Matrix
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