(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find a plane perpendicular to the two planes, X+Y=3 and X+2y-z=4

I know i take the cross product of both so i get

<1,1,0> and <1,2,-1>

But when i do the cross product i get x-y+z

book tells me x-y-z

what am i doing wrong? Not sure why the z is negative. The cross product formula tells me. that the only the J component is negative. (Using Rogawskis Multivariable book. Page. 698, 13.4.)

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# Homework Help: Cross Product of Two Planes

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