- #1
char808
- 27
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Homework Statement
The whole problem is :
Find eqn of plane through (2, 0, 2) perpendicular to vectors <1, -1, 2> and <-1, 1, 0>
I am trying to figure out if I am making an error with cross products here...
Find the normal (perpendicular) vector of <1, -1, 2> and <-1, 1, 0>
Homework Equations
Cross products equation... <1, -1, 2> X <-1, 1, 0>
The Attempt at a Solution
Normal Vector: <-2, -3, 0>
So the plane equation would be
-2(x-2) -3(y-0)+0(z-2) =0
-2x-3y=4