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## Homework Statement

The whole problem is :

Find eqn of plane through (2, 0, 2) perpendicular to vectors <1, -1, 2> and <-1, 1, 0>

I am trying to figure out if I am making an error with cross products here...

Find the normal (perpendicular) vector of <1, -1, 2> and <-1, 1, 0>

## Homework Equations

Cross products equation... <1, -1, 2> X <-1, 1, 0>

## The Attempt at a Solution

Normal Vector: <-2, -3, 0>

So the plane equation would be

-2(x-2) -3(y-0)+0(z-2) =0

-2x-3y=4