- #1

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Here's what I did:

tan^-1(67/100)

theta = 33.82 degrees

Vx = Vxocos(33.82)

Vx = 1.20m/s * cos(33.82)

Vx = 0.997m/s

and since the current is moving in the opposite direction it would be -0.997m/s.

Does that sound about right?

- Thread starter sundrops
- Start date

- #1

- 55

- 0

Here's what I did:

tan^-1(67/100)

theta = 33.82 degrees

Vx = Vxocos(33.82)

Vx = 1.20m/s * cos(33.82)

Vx = 0.997m/s

and since the current is moving in the opposite direction it would be -0.997m/s.

Does that sound about right?

- #2

- 55

- 0

So obviously my method of getting the answer was flawed aswell. Is there another way to solve this problem?

- #3

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- #4

learningphysics

Homework Helper

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1.20 m/s is the speed of the swimmer in still water. Not his total speed. His velocity is 1.20 m/s in the x-direction (direction across river), and v in the y-direction(along the river), where v is the river speed. How long does it take him to cross the river?sundrops said:

So obviously my method of getting the answer was flawed aswell. Is there another way to solve this problem?

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