A swimmier heads across a river, swimming at 1.20m/s relative to still water. It arrives at a point 67.0 m downstream from the oint directly across the river, which is 100.m wide. What is the speed of the river current?(adsbygoogle = window.adsbygoogle || []).push({});

Here's what I did:

tan^-1(67/100)

theta = 33.82 degrees

Vx = Vxocos(33.82)

Vx = 1.20m/s * cos(33.82)

Vx = 0.997m/s

and since the current is moving in the opposite direction it would be -0.997m/s.

Does that sound about right?

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# Homework Help: Crossing a River

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