A swimmier heads across a river, swimming at 1.20m/s relative to still water. It arrives at a point 67.0 m downstream from the oint directly across the river, which is 100.m wide. What is the speed of the river current? Here's what I did: tan^-1(67/100) theta = 33.82 degrees Vx = Vxocos(33.82) Vx = 1.20m/s * cos(33.82) Vx = 0.997m/s and since the current is moving in the opposite direction it would be -0.997m/s. Does that sound about right?