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Can anyone help explaining how during a phase transition, crystal will be more symmetric at high temperature

- Thread starter vani_lj
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Can anyone help explaining how during a phase transition, crystal will be more symmetric at high temperature

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DrDu

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The relevant quantity is the free energy F=U-TS. At T=0 the ordered state will be more stable however at some critical temperature, the S term will outweigh the U term and the symmetric state with <S_z>=0 will be favoured.

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Can this b xplained on d basis of crystal structure?

- #4

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TbVO4 is one of the textbook examples, it is tetragonal (high symmetry) at high temperature and orthorhombic (lower symmetry) at low temperature.

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@ M Quack : Thank You

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