1. The problem statement, all variables and given/known data two identical CS amplifiers connected in cascade. 1st stage fed with vsigand Rsig=100k ohm. load RL= 10k ohm connected to drain of 2nd stage. each MOSFET biased at ID = 0.25mA and VOV=0.25V. assume VA is very large. Each stage has RD=10k ohm. a) sketch equivalent circuit of two-stage amplifier b) find overall voltage gain Gv 2. Relevant equations ID = (1/2)*kn*(VOV)2 <-- sat. gm = knVOV ro = |VA|/ID GV=AV=-gm*RD || RL = -gm*RO Vo = -(gmvgs)(RD||ro) 3. The attempt at a solution i sketched the small signal circuit on paper but I'll probably show it later. solving for kn i get 8mA/V2. and gm=2mA/V. If VA is infinite then ro is infinite, and RO=ro||RD=RD. I get for 1st stage AVo1=GVo1=-20V. To find the relationship for 2nd stage I did Vo1=Vi2=-(gmVi1)(RO) and Vo2=-(gmVi2)(RO)=(gm)2(RD||ro)2Vi2 then GVo2=Vo2/Vi2=400V. but is that right? I get a positive gain so I think i did it wrong.