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Cube of wires

  1. Jul 18, 2011 #1
    A wire is broken down into 12 pieces so that each piece is of resistance 1R. The pieces are joined together to form a cube. What would be the resistance at the diagnols of the 4 faces of the cube?
     
  2. jcsd
  3. Jul 18, 2011 #2

    tiny-tim

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    welcome to pf!

    hi hamzanaveed! welcome to pf! :wink:
    i don't understand what you mean (and also a cube has 6 faces) :confused:

    anyway, show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
     
  4. Jul 18, 2011 #3
    I am assuming you mean the resistance at two diagonal vertices of the cube. Try plotting out all of the different paths that current can take from point A to point B, and then go from there. see if you can put it in the form of a circuit diagram. Drawing a picture of a cube (okay, drawing a 2-dimensional representation of a cube) helps a lot.
     
  5. Jul 18, 2011 #4

    A.T.

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    Here is a similar one:

    A circuit has N nodes. Each node is connected to every other node via a resistor R. What is the total resistance between two nodes?


    The trick in both questions is to find the nodes that are equipotential.
     
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