1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Curl of a vector field

  1. Feb 21, 2011 #1
    Find the curl of the following vector field

    u = yi+(x+z)j+xy^(2)k

    Now using the method Ive bin taught similar to finding determinant of 3x3 matrix here is my answer

    i(2yx-1) -j(y^2) +k(0)

    Just looking for confirmation if this is correct or any basic errors I have made thank you.
  2. jcsd
  3. Feb 21, 2011 #2

    Char. Limit

    User Avatar
    Gold Member

    Confirmed that it is correct, then.
  4. Feb 21, 2011 #3
    Thank you Char.limit just a follow up question I am asked:

    Find (curl u).v

    v = xi+(y^(2) - 1)j+(1-x^(2))k

    Is that just the dot product of the vector v and the curl established for u. Thank you
  5. Feb 21, 2011 #4

    Char. Limit

    User Avatar
    Gold Member

    Yes it is. And you can just ignore the k part completely.
  6. Feb 21, 2011 #5
    So would that give me:

    (2x^(2) y -x) +(y^(4) - y^(2))

    Also do I still need the i j k notations??
  7. Feb 21, 2011 #6


    User Avatar
    Science Advisor
    Homework Helper

    YOu have obtained a scalar. There's no more unit vector involved.
  8. Feb 21, 2011 #7
    Oh ok so my final answer would just be 2x^(2) - x +y^(4) - y^(2)

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Curl of a vector field
  1. Curl of a vector field (Replies: 11)