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Curl of a vector field

  1. Feb 21, 2011 #1
    Find the curl of the following vector field

    u = yi+(x+z)j+xy^(2)k

    Now using the method Ive bin taught similar to finding determinant of 3x3 matrix here is my answer

    i(2yx-1) -j(y^2) +k(0)

    Just looking for confirmation if this is correct or any basic errors I have made thank you.
  2. jcsd
  3. Feb 21, 2011 #2

    Char. Limit

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    Confirmed that it is correct, then.
  4. Feb 21, 2011 #3
    Thank you Char.limit just a follow up question I am asked:

    Find (curl u).v

    v = xi+(y^(2) - 1)j+(1-x^(2))k

    Is that just the dot product of the vector v and the curl established for u. Thank you
  5. Feb 21, 2011 #4

    Char. Limit

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    Yes it is. And you can just ignore the k part completely.
  6. Feb 21, 2011 #5
    So would that give me:

    (2x^(2) y -x) +(y^(4) - y^(2))

    Also do I still need the i j k notations??
  7. Feb 21, 2011 #6


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    YOu have obtained a scalar. There's no more unit vector involved.
  8. Feb 21, 2011 #7
    Oh ok so my final answer would just be 2x^(2) - x +y^(4) - y^(2)

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