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## Homework Statement

compute the curl of:

[tex]\vec{r}[/tex]

and

[tex]\frac{\vec{r}}{r^3}[/tex]

## Homework Equations

[tex]\vec{r}=x\hat{x}+y\hat{y}+z\hat{z}[/tex]

[tex]r^3=(x^2+y^2+z^2)^\frac{3}{2}[/tex]

## The Attempt at a Solution

I figured out that the curl of [tex]\vec{r} = 0[/tex] as my book says it should be....

however...I also need to prove the second vector field up there also is equal to 0...Is it as simple as saying this?:

since [tex]∇\times\vec{r}=0 [/tex]... therefore, [tex]∇\times\vec{r}(\frac{1}{r^3})=0[/tex] as well. ?????

My book states that we should be able to see that these equal zero before doing the calculations to save us time

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