How Does a Changing Magnetic Field Affect Nearby Electric Fields?

In summary, the magnetic field is uniform and out of the page inside a circle of radius R, and is essentially zero outside the circular region. The magnitude of the magnetic field is changing with time and can be represented as (B0 + bt^3). Using Faraday's Law, we can determine the direction and magnitude of the "curly" electric field at two different locations, P and Q. The direction of the electric field at P is to the left of the center and the magnitude can be found by using the relationship between emf and the integral of the non-Coulomb electric field around a closed path. At location Q, the direction of the electric field is to the right of the center and the magnitude can be determined
  • #1
DeadFishFactory
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Homework Statement



23-068-E_inside_and_outside_magnet.jpg


The magnetic field is uniform and out of the page inside a circle of radius R, and is essentially zero outside the circular region (see the figure). The magnitude of the magnetic field is changing with time; as a function of time the magnitude of the magnetic field is (B0 + bt^3). r1 = 6.4 cm, r2 = 63 cm, B0 = 1.5 T, b = 1.4 T/s3, t = 0.8 s, and R = 15 cm.


(a) What is the direction of the "curly" electric field at location P, a distance r1 to the left of the center (r1 < R)?

(b) What is the magnitude of the electric field at location P? (Hint: remember that "emf" is the integral of the non-Coulomb electric field around a closed path.)

(c) What is the direction of the "curly" electric field at location Q, a distance r2 to the right of the center (r2 > R)?

(d) What is magnitude of the "curly" electric field at location Q?


Homework Equations



E∫dA = emf
emf=dΦB/dT
ΦB = BxA


The Attempt at a Solution



I have no clue. It says to use the E∫dA = emf, but emf is not given. That (B0+bt^3) is just confusing me.
 
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  • #2
Faraday's Law says emf = -dΦ/dt. Does that help?
 
  • #3
Not much because I don't know what to do with it. What would the flux be? Would it be
emf = -dΦ/dt

Φ = BxA

emf = (-d/dt)BxA?

Does B = B0 + bt^3?
 
  • #4
DeadFishFactory said:
Not much because I don't know what to do with it.
Then you need to read your textbook and learn about Faraday's Law.
What would the flux be? Would it be
emf = -dΦ/dt

Φ = BxA

emf = (-d/dt)BxA?
I would not put a cross in between because it implies a cross product and that's not we have here. Actually we have a dot product. You also need to learn about magnetic flux and how it is defined. Flux is not just "Field times area". Only the normal component to the area contributes to the flux.
Does B = B0 + bt^3?
Yes.
 
  • #5


As a scientist, it is important to approach any problem with a clear and logical thought process. Let's break down the given information and equations to come up with a solution.

Firstly, we are given a magnetic field that is changing with time, with a magnitude of (B0 + bt^3). This means that the magnetic field is increasing with time, as t^3 is a cubic term and b is a positive constant. We are also given the values of r1, r2, B0, b, t, and R.

(a) To determine the direction of the "curly" electric field at location P, we can use the right-hand rule. Since the magnetic field is increasing with time, the direction of the electric field will be counterclockwise. This is because the change in magnetic field induces a non-Coulomb electric field that is perpendicular to it, according to Faraday's law.

(b) To calculate the magnitude of the electric field at location P, we can use the equation E∫dA = emf, where emf is the electromotive force, or the induced voltage. From Faraday's law, we know that emf is equal to the change in magnetic flux over time. In this case, the change in magnetic flux is equal to the change in magnetic field (B0 + bt^3) multiplied by the area of the circle, πr1^2. Therefore, we can write:

E∫dA = (B0 + bt^3)πr1^2/t = (1.5 + 1.4(0.8)^3)π(0.064)^2/0.8 = 0.047 T

(c) To determine the direction of the "curly" electric field at location Q, we can again use the right-hand rule. Since the magnetic field is increasing with time, the direction of the electric field will be clockwise, opposite to the direction at location P.

(d) To calculate the magnitude of the electric field at location Q, we can use the same equation as in part (b), but with the new values for r2 and t:

E∫dA = (B0 + bt^3)πr2^2/t = (1.5 + 1.4(0.8)^3)π(0.63)^2/0.8 = 0.232 T

In
 

1. What are "Curly Electric Fields"?

"Curly Electric Fields" refer to electric fields that are not uniform and have a changing magnitude and direction over time. They are also known as non-conservative electric fields.

2. How are "Curly Electric Fields" created?

"Curly Electric Fields" can be created by changing magnetic fields or by having an uneven distribution of charges. They can also be created by varying the electric potential in different areas.

3. What are some applications of "Curly Electric Fields"?

"Curly Electric Fields" have various applications in fields such as electromagnetism, electronics, and telecommunications. They are used in devices such as motors, generators, and transformers. They are also used in wireless charging and induction heating.

4. How do "Curly Electric Fields" affect charged particles?

The presence of "Curly Electric Fields" can cause charged particles to experience a force and move in a curved path. This is because the electric field is changing in magnitude and direction, causing the particle to change its direction of motion. This phenomenon is known as the Lorentz force.

5. Can "Curly Electric Fields" be shielded or blocked?

Yes, "Curly Electric Fields" can be shielded or blocked by using conductive materials. This is because the conductive materials can create an equal and opposite electric field, canceling out the "Curly Electric Field". This is the principle behind Faraday cages, which are used to shield against electric fields.

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