An electric circuit consists of 3 identical resistors of resistance R connected to a cell of emf E and negligible internal resistance. What is the magnitude of the current in the cell? (in the diagram two of the resistors are in parallel with each other then the other in series with that pair)
I = V/R
1/R = 1/r + 1/r +...
R = r1 + r2
The Attempt at a Solution
It's a multiple choice question and the answer is 2E/3R but I can't see where that has come from.
If I said that R was 2 ohms then the combined resistance would be 3 ohms but that doesn't help. I can't see where the 2/3 has come from please help, thank you