1. The problem statement, all variables and given/known data If IB and IC (IB = Base current and IC = Collector current) of bipolar junction transistor are 1mA and 100 mA respectively, determine its current amplification ratio in common emitter configuration. 2. Relevant equations IC=β*IB Where β = current gain = [itex]\alpha[/itex]/([itex]\alpha[/itex]-1) (is this the same as current amplification ratio)??? Where [itex]\alpha[/itex] = IC/IE (IE = Emitter current) 3. The attempt at a solution I understand that whatever signal is input in through the base is amplified out through the collector. I found this page very helpful http://230nsc1.phy-astr.gsu.edu/hbase/solids/trans2.html#c6 β = IC/IB = 100mA/10mA = 100 Was this problem really that easy?! Or am I missing something big here? Professor usually assigns pretty involved homework problems. Thank you.