# Current Amplification Ratio

1. Mar 2, 2014

### TehBigBoss

1. The problem statement, all variables and given/known data
If IB and IC (IB = Base current and IC = Collector current) of bipolar junction transistor are 1mA and 100 mA respectively, determine its current amplification ratio in common emitter configuration.

2. Relevant equations
IC=β*IB
Where β = current gain = $\alpha$/($\alpha$-1) (is this the same as current amplification ratio)???

Where $\alpha$ = IC/IE (IE = Emitter current)

3. The attempt at a solution
I understand that whatever signal is input in through the base is amplified out through the collector.

β = IC/IB = 100mA/10mA = 100

Was this problem really that easy?! Or am I missing something big here? Professor usually assigns pretty involved homework problems.

Thank you.

2. Mar 2, 2014

### Staff: Mentor

100 is right. Too easy?

3. Mar 2, 2014

### TehBigBoss

Well he usually give us problems where we have to derive our own equations to use. This one seemed too much like a plug and chug question considering that equation was all over the lecture and book. Thank you though!

4. Mar 2, 2014

### Staff: Mentor

The solution would have been slightly more challenging had you been told that it was the emitter current that was 100mA, determine β.