The cell supplies 8.1×10^3 J of energy when 5.8×10^3 C of charge moves completely round the circuit. The current in the circuit is constant.
A. Deduce that the e.m.f of the cell E is about 1.4 V
B. The resistor R has resistance 6.0 Ω. The potential difference between its terminals is 1.2 V. Determine the internal resistance r of the cell.
C. Calculate the power dissipated by the resistor R.
The Attempt at a Solution
For A, I noticed that if you divide 8.1 x 10^3J by 5.8 x 10^3C you get 1.39 which is very close to what I am supposed to deduce (1.4). Is this a correct way of finding what the e.m.f of the cell is?
For B, I think I need the equation E = DeltaV + (I)(r) . In this equation what does E stand for? Can someone help me solve for I?
For C, I'm not even sure how to go about this other than for this equation: P=I^2 * R