An emf of 10V is connected to the RL circuit (R = 10 Ohms, L = 1.0 H)
shown below for long, long time (the switch is in position 1). Then, at t = 0
the switch is thrown into position 2. Find the current in the circuit at t = 0.2
s. When will the current drop to 0.001 A?
"Discharge" of RL circuit: I(t) = I0e-Rt/L
The Attempt at a Solution
This looks like simple plug-in problem:
I0 = E / R after "long, long time"
E = 10 V, R = 10 Ohms, L = 1 Henry
I(0.2) = 0.135 A
I set I = .001 A and solved for t:
t = 0.691 s
Are my answers correct and did i do this problem correctly?
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