Current circuit

1. Jul 9, 2011

Lindsayyyy

1. The problem statement, all variables and given/known data

I want so show that U1=U*R2/(R1+R2) (sorry latex didn't work for me right now, don't know why)

2. Relevant equations

3. The attempt at a solution

I know the solution but I don't understand one step:
The solution says the following: the fall of voltage at U1 = R2*I (I is the current which comes from U). Why is that? Thats doesn't make sense to me, because I thought the current "splits" at this spot so I have: I=I1+I2.
Why does the solution say it's U=R2*I

Thanks for the help

File size:
7.3 KB
Views:
76
2. Jul 9, 2011

jeannagui

well u is the emf of the source right ?
but what is this ---------u1 ? wat's U1

3. Jul 9, 2011

Lindsayyyy

I don't know how to describe it properly in english, but I think it's the voltage which drains off. I think the english term is voltage divider. But as I'am writing this I think I oversaw something.
The resistances are in series so the current is everywhere the same. Is this the right solution for the problem?

4. Jul 9, 2011

I like Serena

That's because the current does not really split.
The point where U1 is measured is not attached to anything, so no current flows.

This is indeed *only* a voltage divider.
Of course, when something (significant) is attached, the currents and voltages will change.

5. Jul 9, 2011

Lindsayyyy

Ok, I didn't recognize that I have to handle it this way. Thanks for the help