INTRODUCTION: I had been doing some current electricity froblems but now and then i'm having some problems with the distribution of current.I'm really confused. I have attached a figure with this thread, in which i've tried to combine all situations of current distribution in which i'm facing problems. THE EXACT PROBLEM: In the given figure, the current enters at A and leaves at B.What would be the current distribution in the wires in each of the following conditions:- (a)If all the wires, i.e. AB,AD,CD,BC have identical resistances. (b)If only AB has some resistance and the other three wires in the rectangle have 0 resistance. (c)If the resistance of AD is more than that of AB. (d)If the resistance of AD is less than that of AB. You may add if there are any more conditions which will differ from the above. WHAT MY BRAIN SUGGESTED: (a)I think current i will distribute as i/2 in each of the two wires AB and AD as they are symmetrical. (b) Here the whole current i will flow through AB. (c)&(d) I feel that the current will distribute accordingly, i.e. more current will flow through less resistance wire.But here i'm getting totally confused. CONFUSION: To explain why i'm getting confused, lets take an example. Let's say each of the wires in the rectangle, i.e.AB,AD,BC,CD has resistance 2 ohm each. Now according to (a) current i should distribute as i/2 in each of AB and AD. But again we note that the combined resistance of AD,CD and BC is 6 ohm. Now my question is:- "WHILE DISTRIBUTION OF CURRENT i AT THE JUNCTION A, SHOULD WE CONSIDER THE RESISTANCE OF AB AND AD ONLY OR SHOULD WE CONSIDER THE RESISTANCE OF AB AND THE COMBINED RESISTANCE OF (AD,CD,BC)?" CONCLUSION: I know that it's really difficult to understand someone's problem through text but i've tried my best to explain it.And believe me, I'm reall really confused.Please help.Thanks.