# Current flowing in a Resistor

1. May 20, 2013

### kingstar

1. The problem statement, all variables and given/known data
AB, BC and CD are three resistors connected together at B and C. AB = 12 ohms, BC = 7 ohms, CD = 6 ohms. A battery of emf 48V and internal resistance 0.5 ohms has it positive pole connected to B and its negative connected to D. A battery of emf 74V and internal resistance 1 ohm has its positive pole connected to A and its negative pole connected to C. Find the current flowing in BC.

2. Relevant equations
E = I(R +r)
V = IR

3. The attempt at a solution

To be honest, I'm clueless.

I tried using E = I(R + r) but unsure how to add up resistors in a triangle :S

2. May 20, 2013

### barryj

I'm not sure of your circuit. Whnat does "connected together at B and C mean?

3. May 20, 2013

### kingstar

I am not exactly sure either, I've just copied word for word the question my professor has given.

4. May 20, 2013

### barryj

You should be able to draw the schematic with two current loops. Using Kirchoff's law, you can have two equations with two currents. Solve them simultaneously.

5. May 20, 2013

### phinds

Then tell your professor that he has not provided enough information for there to be a solution.

6. May 20, 2013

### Staff: Mentor

An interpretation that seems to fit the bill:

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7. May 20, 2013

### barryj

I think that there are 3 resistors in series. There are 4 terminals. 12 ohms between a and B, 7 ohms between B and C and 6 ohms between C and D. 48 volt battery with .5 ohm internal resistance connected with + to B and - to D.

8. May 20, 2013

### kingstar

Using gneil's diagram I'd just split it into 2 loops and then as 'barryj' suggested, solve them simultaneously.

Will try this and check if its right.

Thanks.