In the circuit of Fig. 16(a), the voltage v has the periodic waveform shown in Fig. 16(b) with a period of 4 us and an amplitude of 20 V.
i = Cdv/dt
v = Ldi/dt
The Attempt at a Solution
Assuming that x is constant (at its average value), draw a dimensioned sketch of the waveform
of iL(t) and determine its maximum and minimum values.
x = 5 (as duty cycle is 1/4 => 20/4)
Therefore at begining of cycle v = 20 => inductor has drop of 15v across it
using v = Ldi/dt
di/dt = 15/2e-3
= 7500 Amp per sec
i = 7.5mA
So in one microsecond the current in the inductor goes from 0 to 7.5mA agreed? I've presumed the charge is linear, is this correct? Why?
Now after 1us the v is 0 volts for 3us. This means the inductor's magnetic field will collapse into the capacitor or resistor or both?