# Current in a Resistor-Capacitor Circuit with -5V EMF

• swechan02
In summary, the conversation is about a circuit with an Emf of -5V, one 5ohm resistor, and one 20 F capacitor. The question is what is the current of the circuit and if there will be any effects on the current because of the capacitor. It is mentioned that the post was made in the wrong section of PF and it is not appropriate to expect others to do the work without attempting it first.
swechan02
If there is a circuit with--Emf -5V and one 5ohm resistor and one 20 F capacitor, what is the current of the circuit?
Will there be any effects on current because of capacitor?

Please note these THREE points:

1. You posted in the wrong section of PF. Did you miss the Homework Help section at the very TOP of the PF list?

2. You multiple post this in the classical physics section. This is a no-no. You may want to read PF's guildelines before you proceed.

3. You should not expect anyone to do your work for you. Please read the Sticky in the Homework help section and note that you should, at the very least, show what you have attempted to do so that we know where we should start in presented to you an explanation.

Zz.

The current in a resistor-capacitor circuit with a -5V EMF can be calculated using Ohm's Law (I = V/R) and the formula for capacitive reactance (Xc = 1/(2*pi*f*C)). In this case, the frequency (f) is not given, so we cannot calculate the capacitive reactance. Therefore, we cannot determine the current without additional information.

However, we do know that the capacitor will have an effect on the circuit. When the circuit is first connected, the capacitor will act as an open circuit and no current will flow. As the capacitor charges, the current will gradually increase until it reaches its maximum value determined by the resistance and capacitance values.

Once the capacitor is fully charged, the current will decrease to zero again. This cycle will continue as long as the circuit remains connected and the EMF is maintained. Therefore, the presence of the capacitor will have a significant effect on the current in the circuit.

In summary, without the frequency information, we cannot determine the exact current in this circuit, but we can conclude that the capacitor will have a significant impact on the current behavior.

## 1. What is a resistor-capacitor circuit?

A resistor-capacitor (RC) circuit is an electrical circuit that contains both a resistor and a capacitor. The resistor restricts the flow of current in the circuit, while the capacitor stores electrical charge. Together, these components can be used to control the flow of electricity in a circuit.

## 2. What is the purpose of a -5V EMF in a resistor-capacitor circuit?

The -5V EMF (Electromotive Force) in a resistor-capacitor circuit is used to provide a voltage source for the circuit. This voltage helps to charge the capacitor and create a potential difference between the two plates of the capacitor. This potential difference is what allows the capacitor to store electrical charge.

## 3. How does a resistor affect the current in a resistor-capacitor circuit?

A resistor affects the current in a resistor-capacitor circuit by restricting the flow of current through the circuit. The higher the resistance of the resistor, the lower the current will be. This is because the resistor resists the flow of electricity, causing a drop in voltage and a decrease in current.

## 4. How does a capacitor affect the current in a resistor-capacitor circuit?

A capacitor affects the current in a resistor-capacitor circuit by storing electrical charge. When a capacitor is fully charged, it acts as an open circuit and blocks the flow of current. As the capacitor discharges, it allows more current to flow through the circuit. Therefore, the current in a resistor-capacitor circuit is inversely proportional to the capacitance of the capacitor.

## 5. What is the equation for calculating the current in a resistor-capacitor circuit?

The equation for calculating the current in a resistor-capacitor circuit is I = V/R, where I is the current, V is the voltage, and R is the resistance. In a circuit with a -5V EMF, the current can be calculated as I = (-5V)/R. This means that the current will decrease as the resistance increases, and vice versa.

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