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Current in a solution

  1. Apr 10, 2009 #1
    I don't even know what equation to use!

    In an ionic solution, 5.0*10^15 positive ions with +2e charge pass to the right each second while 6.0*10^15 negative ions with charge -e pass to the left.

    What is the magnitude of current in the solution?


    (5.0*10^15)*(2*1.6*10^-19) - (6.0*10^15)*(1.6*10^-19)=8.3*10^-4
     
  2. jcsd
  3. Apr 10, 2009 #2

    rl.bhat

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    Check the calculation.
     
  4. Apr 10, 2009 #3
    my calculation was wrong, when I recalculated it i got 6.4E-4, and that was still wrong
    What equation should i use?
     
  5. Apr 10, 2009 #4

    rl.bhat

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    There must be two different solutions in the electrolyte. So when +2e charge from one solution moving toward right,-2e charge is moving towards left. This adds to -e charge from the second solution. So net flow of charge is -3e towards left.
     
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