Current in a solution

  • Thread starter chainsaw
  • Start date
  • #1
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I don't even know what equation to use!

In an ionic solution, 5.0*10^15 positive ions with +2e charge pass to the right each second while 6.0*10^15 negative ions with charge -e pass to the left.

What is the magnitude of current in the solution?


(5.0*10^15)*(2*1.6*10^-19) - (6.0*10^15)*(1.6*10^-19)=8.3*10^-4
 

Answers and Replies

  • #2
rl.bhat
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Check the calculation.
 
  • #3
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my calculation was wrong, when I recalculated it i got 6.4E-4, and that was still wrong
What equation should i use?
 
  • #4
rl.bhat
Homework Helper
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There must be two different solutions in the electrolyte. So when +2e charge from one solution moving toward right,-2e charge is moving towards left. This adds to -e charge from the second solution. So net flow of charge is -3e towards left.
 

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