(adsbygoogle = window.adsbygoogle || []).push({}); 1. the problem

In Figure 27-69 (see attached), the ideal each resistance is 4.50 and V1 = 11.0 V.

(a) What is the size and direction of current i1? (Take upward to be positive.)

(No Response)[-2.44] A

(b) What is the size and direction of current i2? (Take upward to be positive.)

(No Response)[-1.33] A

(c) At what rate is energy being transferred at the 4.00 V battery and is the battery supplying or absorbing energy?

(No Response)[5.33] W (No Response)[ supplying ]

(d) At what rate is energy being transferred at the 11.0 V battery and is the battery supplying or absorbing energy?

(No Response)[41.6] W (No Response)[ supplying ]

Attempted Solution

Help needed with part b.

for part a: we ignored the right hand part of the cirucuit, and just did the left-most loop. Then we summed the voltages and set them to zero, and got the correct answer.

for part b: We looked at the two right loops and combined them by saying that there are two resistors in parallel which can be replaced by [tex]R_{eq}=\frac{1}{R}+\frac{1}{R})^{-1}[/tex]. Then we tried ignoring the left loop and summing the voltages in the middle loop (with the top right resistor replaced by R_eq) and setting everything equal to zero. That's the wrong answer.

Frankly, I don't understand why [tex]i_2\neq i_1[/tex].

And the bloody final is tomorrow

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# Homework Help: Current in multi-loop circuit

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