Using Kirchhoff's rules for the instantaneous currents and voltages in the two-loop circuit, find the current in the inductor as a function of time.(adsbygoogle = window.adsbygoogle || []).push({});

I used Kirchhoff's rule on the left loop consisting of the battery and the right loop which consist of the inductor and gotten the following equations.

E-I_{1}R_{1}- I_{3}R_{2}= 0

L dI_{2}/dt - I_{3}R_{2}= 0

Combining both the equations give me

E-I_{1}R_{1}- L dI_{2}/dt =0

So from here how do we express I_{1}into I_{2}and R to get the differentiate equation form?

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# Homework Help: Current in RL circuit

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