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Using Kirchhoff's rules for the instantaneous currents and voltages in the twoloop circuit, find the current in the inductor as a function of time.
I used Kirchhoff's rule on the left loop consisting of the battery and the right loop which consist of the inductor and gotten the following equations.
EI_{1}R_{1}  I_{3}R_{2} = 0
L dI_{2}/dt  I_{3}R_{2} = 0
Combining both the equations give me
EI_{1}R_{1}  L dI_{2}/dt =0
So from here how do we express I_{1} into I_{2} and R to get the differentiate equation form?
I used Kirchhoff's rule on the left loop consisting of the battery and the right loop which consist of the inductor and gotten the following equations.
EI_{1}R_{1}  I_{3}R_{2} = 0
L dI_{2}/dt  I_{3}R_{2} = 0
Combining both the equations give me
EI_{1}R_{1}  L dI_{2}/dt =0
So from here how do we express I_{1} into I_{2} and R to get the differentiate equation form?
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