1. The problem statement, all variables and given/known data The currents are flowing in the direction indicated by the arrows. A negative current denotes flow opposite to the direction of the arrow. Assume the batteries have zero internal resistance. A) Find the current through the 14.4Ω resistor and the 8.6 V battery at the top of the circuit. Answer in units of A. B) Find the current through the 23.2 Ω resistor in the center of the circuit. Answer in units of A. 2. Relevant equations Kirchhoff's Junction and Loop Rules 3. The attempt at a solution By applying the Kirchhoff's voltage law to the above loop I get 8.6V - (23.2Ω)I1 - (14.4Ω)I = 0 23.2I1 + 14.4I = 8.6 ..............................(1) Applying the Kirchhoff's voltage law to the down loop I get 16.4V + (23.2Ω)I1 = 0 I1 = - 0.71A Substitute this value in the eq(1) 8.6V + (23.2)(0.71) = 14.4I I = 1.74A Therefore the current passes through the battery 8.6V and the resistance 14.4Ω is 1.74A For Part B, I thought that the current would be equal to I1 which I already solved for in Part A, so the current would be -0.71 A. I've pretty much worked everything out but I was hoping if someone could tell me if I was doing it right or not. I'm not too confident when it comes to these problems. Any comments would be very helpful. Thanks!