# Current through diode

1. Jun 30, 2010

### kliker

1. The problem statement, all variables and given/known data

find current through each diode, suppose that they are ideal (use the second approach)

[PLAIN]http://img30.imageshack.us/img30/102/86772682.jpg [Broken]

R is 10kohms
3. The attempt at a solution

a) (12-0.7)/10k = 1.13 mA

b) 0 because diode will be open, actually i added up the two voltate sources and i have a voltage source of 16Volts where + is connected with diodes - and - is connected with diodes + so its reverse biased, hence current will be 0

c) i added up the voltage sources i have 10 volts and its not reversed biased diodes voltage source will be 0.7

hence

(15-0.7)/10k = 1.43 mA

d) added up voltage sources i had a source of 2 volts

hence

(2-0.7)/10000 = 0.13mA

am i correct?

Last edited by a moderator: May 4, 2017
2. Jun 30, 2010

### n.karthick

Yeah a,b and d are correct, but in (c), the voltage across diode and resistor is 10 v and not 15 v as you have put in the equation.

3. Jun 30, 2010

### kliker

you are right, thanks a lot