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## Homework Statement

Consider the circuit shown in the figure . Suppose the four resistors in this circuit have the values R

_{1}= 12 [tex]\Omega[/tex], R

_{2}= 6.4 [tex]\Omega[/tex], R

_{3}= 7.0 [tex]\Omega[/tex], and R

_{4}= 13 [tex]\Omega[/tex], and that the emf of the battery is [tex]\epsilon[/tex] = 18V .

A. Find the current through each resistor using the rules for series and parallel resistors.

B. Find the current through each resistor using Kirchhoff's rules.

http://www.flickr.com/photos/58789079@N08/5385574045/ [Broken] by Tetzsc, on Flickr

## Homework Equations

V=IR

R

_{eq}= 1/R

_{1}+1/R

_{n}

R

_{eq}= R

_{1}+R

_{n}

## The Attempt at a Solution

First I identify R

_{2}& R

_{4}as series circuits in parallel with R

_{3}and solve for the total resistance across these lines giving me 5.14[tex]\Omega[/tex]

I know that I

_{1}-I

_{2}-I

_{3}-I

_{4}= 0 and that current will take the path of least resistance.

This is where I'm stuck. I know that the current leaving the R

_{2}+R

_{4}& R

_{3}will recombine through R

_{1}, but I'm really not sure how to find each individual current.

R

_{p}=5.14[tex]\Omega[/tex]

R

_{t}=17.14[tex]\Omega[/tex]

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