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Current through source in AC circuit with R & LC in parallel
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[QUOTE="Delta2, post: 6093631, member: 189563"] I think your answer (and the associated reasoning) is correct but it can't be solved in a simpler way. We know that when we have elements in parallel the total impedance is computed in a similar way like when we have resistances in parallel. In this circuit it would be $$\frac{1}{Z}=\frac{1}{Z_R}+\frac{1}{Z_{L+C}} \text{(1)}$$ where ##Z## is the total impedance of the circuit and ##Z_{L+C}## is the total impedance of the branch that contains the L and C. Because L and C are in series it is ##Z_{L+C}=Z_L+Z_C=i{(X_L-X_C)}=i100 Ohm## Also ##Z_R=R=100Ohm## So by (1) you can calculate ##Z##, and then calculate ##I_{rms}=V_{rms}/|Z|## [/QUOTE]
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Current through source in AC circuit with R & LC in parallel
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