(adsbygoogle = window.adsbygoogle || []).push({}); 1. There is a current of 0.25 A in the circuit of the figure

What is the value of the resistance R?

Hockay so. I know the change of voltage throughout the loop is 0.

therefore

0 = E1 - I(R1+R2) - E2 - 1R(unknown)

0 = 6V - 0.25A*18ohm - 12V - 0.25A*R

through algebra i get R=42.

And thats wrong. So i dontk now what im doing wrong.

And it also asks for the power dissipated by R and i dont know whether to use the energy of both batteries or do a long equation with info from the whole circuit or what. I do know how ever that i should use the PR = IV or I^2R or (V^2/R)

thanks a bunch.

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# Homework Help: Currents and resistance

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