How Do You Calculate Currents in a Bridge Circuit?

[Peto]

Referring to the bridge circuit of fig P90, if I=6A, I2=4A, and I3 = 0, find I1, I4, and I5.

I did,
I1=2A
I4=4A
I5=2A

My logic being, since I is 6A, and I2 is 4A, I1 must be the difference, 2A. since I4 is coming from I2 and I3 it should be the sum, (0 + 4A = 4A). and I thought because I5 is coming from I1, it must be 2A.

Is this right?
Thanks for any help!

 

[ideasrule]

Yes.

 

[kerimek]

Yes, your logic is correct. Using Kirchhoff's current law, the sum of the currents at a node must equal zero. Therefore, I1 + I3 = I2 + I4 + I5. Since I3 = 0 and I2 = 4A, I1 must be the difference between I and I2, which is 6A - 4A = 2A. Similarly, I4 must be the sum of I2 and I3, which is 4A, and I5 must be the difference between I1 and I4, which is 2A. Your calculations are correct.