Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Curvature of a Helix

  1. Sep 30, 2008 #1
    1. The problem statement, all variables and given/known data

    Find the curvature of a helix given by the parametric equation r(t)=<acost, asint, bt> where a and b are real numbers

    2. Relevant equations

    I know k=|T'(t)/r'(t)|

    3. The attempt at a solution

    and I believe the answer to be k=b/(a2+b2)1/2, I just don't know how to get there
     
  2. jcsd
  3. Sep 30, 2008 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    First step, write the formula correctly! You can't divide vectors!
    Did you mean k= |T'(t)|/|r'(t)|?

    If so then if r= <a cos t, a sin t, bt>, r'= <-a sin t, a cos t, b> and it's length is [itex]|r'|= \sqrt{a^2 sin^2 t+ a^2 sin^2 t+ b^2}= \sqrt{a^2+ b^2}[/itex], a constant. That means that T, the unit tangent vector is
    [tex]T= \frac{1}{\sqrt{a^2+ b^2}}<-a sin t, a cos t, b>[/tex]

    That's easy to differentiate with respect to t (since that whole first fraction is a constant). Do that and take the length of |T'|. Divide by the length of r' which I've already given you.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Curvature of a Helix
  1. Maximum curvature (Replies: 4)

  2. Defined Helix Banking (Replies: 1)

  3. Constant curvature (Replies: 1)

  4. Radius of curvature (Replies: 3)

Loading...