What Speed Range Keeps a Car from Skidding on a Banked Curve?

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In summary, the problem is asking for the range of speeds at which a 950kg car can travel around a curve with a radius of 30m without skidding, given a coefficient of static friction between the road and tires of 0.3. The first step is to calculate the slope of the curve without friction, and then to add the frictional forces acting parallel to the road in order to prevent skidding. The formula to use is the coefficient of friction times the normal force, and the frictional force will act in a direction to stop the car from slipping.
  • #1
matibtst
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curve banking problem?

Homework Statement



a curve of radius 30m is banked so that a 950kg car traveling 40 km/h can round it even if the road is so icy that the coefficient of static friction is approximately zero. Find the range of speeds at which a car can travel around this curve without skidding if the coefficient of static friction between the road and the tires is 0.3

Homework Equations



This part i really need help in pls may i ask for any equations to use i can't even understand the problem. I can't interpret the free body diagram pls give me a formula ^^

The Attempt at a Solution



none i tried drawing a slope with an object but i don't know how to get the angle of the slope...
 
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  • #2
What class are you taking? What equations are introduced in the chapter that this question is from? You need to show more effort before we can help you much.
 
  • #3
think about this
when the car has maximum speed, friction is down the slope and when speed is minimum, friction is up the slope
 
  • #4
First ignore the friction and calculate the slope of he curve from the icy case. Draw a diagram to show the forces on the car.
 
  • #5
How do i calculate the slope pls.. I'm taking physics natural science and the last formula our pro gave us was the coefficient of friction times normal force is equal to force of friction. so i don't know how to get the slope of the problem i don't even know how to derive where the slope came from sorry
 
  • #7
thank you for the diagram it has been very helpful thank you very much i at least have an idea now on how to sole ^^
 
  • #8
Extending it to the case of friction just involves adding the extra foces, remember that friction will act parrallel to the road in a direction to stop the car slipping.
As you said above, friction force is the normal force * coefficent of friction.
 
  • #9
mgb_phys said:
friction will act parrallel to the road in a direction to stop the car slipping.

I guess frictional force considered in this question is the force acting perpendicular to the road which avoids the car slippin towards or away from centre of the circular track(or any kind of track, maybe call it instantaneous center) at lowest and highest speed at the curve respectively.
the frictional force mgb_phys is considering is the force which gets the car going
 

What is the curve banking problem?

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