Curve integral

  • Thread starter sibiryk
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  • #1
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How can I find average distance from the origin point x=y=0 to
the points of the curve using curve integral.

Curve given by

x=cos(2t), y=3sin(2t), t at [0,pi]

I looked in books I have but there is no info on this.
 

Answers and Replies

  • #2
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sibiryk said:
How can I find average distance from the origin point x=y=0 to
the points of the curve using curve integral.
Curve given by
x=cos(2t), y=3sin(2t), t at [0,pi]
I looked in books I have but there is no info on this.
Find an equation that gives the distance at any value of t. Then integrate it and divide by the interval (def. of average value).
 
  • #3
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I need to find it using curve integral
 
  • #4
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apmcavoy said:
Find an equation that gives the distance at any value of t. Then integrate it and divide by the interval (def. of average value).

Ok. I integrated equation that give the distance.

I got

Integral ((cos^2(2t)+6sin^2(2t))^0.5)*dt integral from 0 to pi

Did I get it right?
 
  • #5
NateTG
Science Advisor
Homework Helper
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sibiryk said:
Ok. I integrated equation that give the distance.
I got
Integral ((cos^2(2t)+6sin^2(2t))^0.5)*dt integral from 0 to pi
Did I get it right?

Close. You need to be more careful with your derivatives and algebra.
 
  • #6
665
0
sibiryk said:
Ok. I integrated equation that give the distance.
I got
Integral ((cos^2(2t)+6sin^2(2t))^0.5)*dt integral from 0 to pi
Did I get it right?
[tex]3^2\neq 6[/tex]

For this case:

[tex]\text{Average}=\frac{1}{\pi}\int_{0}^{\pi}f\left(x\right)\,dx[/tex]

Now it's up to you to find f(x).
 
Last edited:

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