- #1

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the points of the curve using curve integral.

Curve given by

x=cos(2t), y=3sin(2t), t at [0,pi]

I looked in books I have but there is no info on this.

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- Thread starter sibiryk
- Start date

- #1

- 32

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the points of the curve using curve integral.

Curve given by

x=cos(2t), y=3sin(2t), t at [0,pi]

I looked in books I have but there is no info on this.

- #2

- 665

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Find an equation that gives the distance at any value of t. Then integrate it and divide by the interval (def. of average value).sibiryk said:

the points of the curve using curve integral.

Curve given by

x=cos(2t), y=3sin(2t), t at [0,pi]

I looked in books I have but there is no info on this.

- #3

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I need to find it using curve integral

- #4

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apmcavoy said:Find an equation that gives the distance at any value of t. Then integrate it and divide by the interval (def. of average value).

Ok. I integrated equation that give the distance.

I got

Integral ((cos^2(2t)+6sin^2(2t))^0.5)*dt integral from 0 to pi

Did I get it right?

- #5

NateTG

Science Advisor

Homework Helper

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sibiryk said:Ok. I integrated equation that give the distance.

I got

Integral ((cos^2(2t)+6sin^2(2t))^0.5)*dt integral from 0 to pi

Did I get it right?

Close. You need to be more careful with your derivatives and algebra.

- #6

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[tex]3^2\neq 6[/tex]sibiryk said:Ok. I integrated equation that give the distance.

I got

Integral ((cos^2(2t)+6sin^2(2t))^0.5)*dt integral from 0 to pi

Did I get it right?

For this case:

[tex]\text{Average}=\frac{1}{\pi}\int_{0}^{\pi}f\left(x\right)\,dx[/tex]

Now it's up to you to find f(x).

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