# Curve intersection in 3d

1. Oct 8, 2013

### MarcL

1. The problem statement, all variables and given/known data
Show that x=sin(t),y=cos⁡(t),z=sin^2 (t) is the curve of intersection of the surfaces z=x^2 and x^2+y^2=1.

2. Relevant equations

I don't think there aren't really any equations relevant for this maybe except the unit circle..?

3. The attempt at a solution

I don't know how to equate both equation, I remember one problem very vaguely where we replaced the x^2 variable with s but I doubt this is what I have to do. Any insights on how to start this problem?

2. Oct 8, 2013

### Dick

x^2+y^2=1 tells you that you are on the unit circle for x and y. You can certainly parameterize that as x=sin(t), y=cos(t). Why? Then you just have to figure out what z is in terms of t. I really don't think there is much substance to this problem. Why are you confused?

3. Oct 8, 2013

### MarcL

first of all wouldn't it be x=cos(t) and y= sin(t) I mean isn't that what it is on a unit circle? and whoops I just understood what you meant by z, after I figured out x, just plug it in so z=sin^2(t)

4. Oct 8, 2013

### Dick

x=sin(t) and y=cos(t) is just as good a parmetrization of the unit circle as x=cos(t) and y=sin(t). Tell me why?

5. Oct 8, 2013

### MarcL

I thought so because x=1 at t=0 well I thought so but you're right it doesn't change anything when I think about it. So i just put it in this form of parametric equation to just satisfy my first equation?

6. Oct 9, 2013

### Dick

Yes, that's the way to show this parametrization works. x=cos(t), y=sin⁡(t), z=cos(t)^2 is also a good (but different) parametrization of the same intersection.