I am finding the x intercepts of 2(x^3)-6(x^2)-18x+7 . For some reason I am NOT getting it, even though its probably really easy.
The Attempt at a Solution
I set the equation to 0 and then isolated the x's and got
-7 = 2(x^3)-6(x^2)-18x
factored out a 2x and got
-7 = 2x((x^2)-3x-9)
i tried factoring (x^2)-3x-9 and have no idea how.
can someone please explain where to go from here and how to find the zeroes, or if there is another way to do so