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Curve tracer (npn)

  1. Mar 29, 2012 #1
    Hoping this can be cleared up quickly as I have my final exam in 1 hour. My question is for the attached image. I know for pnp transistors that ic=0, and Vce=0 at top right hand corner. However, one thing I don't understand is why the base current starts at 20uA at the bottom, rather than at the top. Help is greatly appreciated!

    Attached Files:

  2. jcsd
  3. Mar 29, 2012 #2


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    Staff: Mentor

    Probably too late for your exam, but it looks wrong to me. 20uA should be the top (smallest Ic) trace, and Ib should step to larger values at the larger Ic values.
  4. Mar 30, 2012 #3
    That's what I thought. Looks like whoever marked it was not paying attention.
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