I'm kinda stuck on this question... my text gives me a simple example, but it's far from enlightening. Just wondered if I could get some help!(adsbygoogle = window.adsbygoogle || []).push({});

"At what point on the curve y = 1 + 2e^x - 3x is the tangent line parallel to the line 3x -y =5?"

Would I just need to simply compare the slopes?

I found the derivative of the curve: y'= 2e^x - 3

So I suppose you just set 2e^x = 3... then you get x = ln(3)/2 ?

Thanks~

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# Homework Help: Curves and parallel lines

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