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Curvilinear coordinate system: Determine the standardized base vectors
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[QUOTE="Karl Karlsson, post: 6387683, member: 667628"] [B]Homework Statement:[/B] Determine the standardized base vectors in the curvilinear coordinate system $$\begin{cases} u_1 = x^2-y^2 \\ u_2 = xy \\ u_3 = z\end{cases}$$ [B]Relevant Equations:[/B] $$\begin{cases} u_1 = x^2-y^2 \\ u_2 = xy \\ u_3 = z\end{cases}$$ How I would have guessed you were supposed to solve it: [ATTACH type="full"]268821[/ATTACH] What you are supposed to do is just take the gradients of all the u:s and divide by the absolute value of the gradient? But what formula is that why is the way I did not the correct way to do it? Thanks in advance! [/QUOTE]
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Curvilinear coordinate system: Determine the standardized base vectors
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