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When this machine takes 0.2 moles of a one atomic ideal gas through this cycle, find the pressure and volume in 1, 2 and 3

OK, I start by finding V_{1}by using the ideal gas law. 4,92 L

This is also V_{2}of course.

Next, using the ideal gas law again, I find that P_{2}is 2 atm, or 203 kPa.

We know that P_{3}is 1 atm, so I try to find V_{3}with the ideal gas law:

V_{3}= nRT_{3}/P_{3}= 0.2*8.3145*455/(101.3*10^3) = 7.47L

This answer is, however, wrong. The correct answer is 7.94L. What is my mistake?

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# Cyclic heat machine

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