A 66.0-cm-diameter cyclotron uses a 530 V oscillating potential difference between the dees.
How many revolutions does the proton make before leaving the cyclotron?
f = (q*B)/(2*pi*m)
The Attempt at a Solution
I find the cyclotron frequency:
f = ((1.6x10^-19)(0.69))/(2*pi*(1.67x10^-27)) = 1.1x10^7 rev/sec
I don't know where to go from there. How do I find the time it takes for the proton to leave the cyclotron?