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Cylinder on inclined plane

  1. Mar 9, 2008 #1
    1. The problem statement, all variables and given/known data
    A block of a certain material begins to slide on an inclined plane when the plane is inclined to an angle of 11.86o. If a solid cyclinder is fashioned from the same material, what will be the maximum angle at which it will roll without slipping on the plane (in degrees)?


    2. Relevant equations



    3. The attempt at a solution
    drew a free body diagram, and have the following equations

    mgsin(theta) + friction = ma
    torque = friction*R = I(angular acceleration) --> friction=(I*angular acceleration)/R
    mgsin(theta) + (I*angular acceleration)/R = ma
    a=R*(angular acceleration) and I = .5MR^2
    ... substitute those in, but then I get

    theta = (inverse sin)[(.5*a)/g] -- how do i solve for a?
     
  2. jcsd
  3. Mar 11, 2008 #2

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    Have you used the relation between [itex]v[/itex] and [itex]\omega[/itex]?
     
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