1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Cylinder on loop

  1. Nov 15, 2005 #1
    A uniform solid cylinder (m=0.710 kg, of small radius) is at the top of a ramp, with height height of 333 cm and which has a loop of radius, R = 49.95 cm at the bottom. Which has friction. The cylinder starts from rest and rolls down the ramp without sliding and goes around the loop. Find the speed of the cylinder at the top of the loop.

    I used conservation of energy
    [tex] mgh= (1/2)mv^2 + (1/2)I \omega ^2 [/tex]
    [tex] mgh = (1/2)mv^2 + (1/2)(1/2)(MR^2)(v/r)^2 [/tex]
    [tex] mgh= (1/2)mv^2 +(1/4)mv^2 [/tex]
    Solving for v gave me [tex] \sqrt (4/3)gh [/tex]
    So plugging in 9.8 for g and 3.33 for h gave me a speed of 6.60 m/s which wasn't right.
    Can someone help me?
  2. jcsd
  3. Nov 15, 2005 #2


    User Avatar
    Homework Helper

    h should be the difference in height between the top of the ramp and the top of the loop.
  4. Nov 15, 2005 #3
    I got it. Thanks
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Cylinder on loop
  1. Loop the loop (Replies: 1)

  2. Loop the Loop (Replies: 10)

  3. Loop the loop (Replies: 3)

  4. Loop a loop (Replies: 4)