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D/A Communications - Minimum bandwidth of a channel

  1. Mar 17, 2013 #1
    1. The problem statement, all variables and given/known data
    attachment.php?attachmentid=56834&stc=1&d=1363552974.png


    2. Relevant equations

    The given channel transfer function and PSDs. Note that the capital Pi symbol in the PSD of the message symbolizes the rectangle function so Sm(f) = 8rect(f/8000)

    3. The attempt at a solution
    attachment.php?attachmentid=56833&stc=1&d=1363552829.jpg

    From my understanding, channel noise is not filtered at this point since it's additive to the signal in the channel.

    I get an answer of B = 0.000164 Hz, which doesn't seem reasonable. Including the negative frequencies, a bandwidth of 2B = 0.000328 Hz still doesn't make much sense to me.
     

    Attached Files:

    Last edited: Mar 17, 2013
  2. jcsd
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