I'm not sure how to differentiate sin^2[3x]. Although, I think it's just d/dx( (sin[3x])(sin[3x]) ). So, just chain and product rules should do it. Is that right?(adsbygoogle = window.adsbygoogle || []).push({});

EDIT: I've followed through with the above method, and I got 3*sin(6x). Is that correct?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# D/dx (sin^2[3x])

Loading...

**Physics Forums | Science Articles, Homework Help, Discussion**