- #1

- 1

- 0

**d orbitals.. 5 or 6???**

hey

i always thought ther wer 5 d orbitals corresponding 2 quantum number m = -2, -1,..., 2

now i read somwhere that ther wud actually be 6 possible sollutions to schrodigner's equation.. i.e. six d orbitals, and th d z-square orbital is a linear combination of two of these 6, giving effectively 5.

it also says that this combination is done because the two orbitals that are combined 'have no independant existance'

firstly,, is this true???? (th place i read this is not exactly reliable)

secondly, if it is, then how can 2 of these 6 orbitals 'have no independant existance'??? wt does this mean?

if it does not hav independant existance, then wt meaning is ther 2 calling it a seperate orbital

also, if ther wer 6 orbitals, shudnt ther be a possibilty of 12 d electrons???

i thot that every valid solution to schrodingers equation(provided it satisfies those 3-4 constraints, continuos, finite etc) is in fact physicaly possible??

thnx.. i know nothin of quantum mechanics so sorry if i asked some ****

HellFeuer