Positive charge is uniformly distributed throughout a non conducting cylindrical shell of inner radius R and outer radius 2R. What radial depth beneath outer surface of the charge distribution is the elctric field strength equal to one half the surface value?(adsbygoogle = window.adsbygoogle || []).push({});

errr

e0 = epsilon 0 the permittivity

e0 EA = Q enc

thus E = Qenc / A e0

to find where E = Qenc / 2Ae0 im totally stumped

your help would be greatly appreciated!

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# Homework Help: Damn Gauss law is so confusing!

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