The displacement amplitude of a lightly damped oscillator with m=0.250kg and k=6400N/m is observed to decrease by 15% in exactly five minutes
a) Calculate the fraction (in%0 of the initial mechanical energy of the oscillator that has been converted to other forms of energy (such as thermal energy) in the five-minute interval.
b)Calculate the Q value of this damped oscillator by first calculation omega initial and gama
omega initial = sqrt(k/m)
gama = b/m
x = A initial exp^(gama t/2)
TE = 1/2kA initial exp^(-gamat)
A(t) = A inital exp^(bt/2m)
T = 2pisqrt(m/k)
The Attempt at a Solution
I have calculated omega inital = 160rads and the period to be .04s. I know there is the relationship between the displacement amplitude and the total energy but I cannot seem to figure out how to relate them. Any help is greatly appreciated.