This is more of a conceptual question.Would overdampening in a circuit (from a resistor) be analogous to stretching a spring past critical distances in a mass-spring system? Or perhaps swinging a pendulum from excessively large angles?
No, not really. Damping (not dampening) refers to the amount of energy lost relative to the amount of energy stored. Overdamping in an electrical circuit is more analogous to a pendulum swinging while submerged in honey. If you pull back the pendulum and release it, it will slowly fall back to its lowest position without oscillating, because the friction with the honey dissipates energy and limits how fast the pendulum can move.This is more of a conceptual question.Would overdampening in a circuit (from a resistor) be analogous to stretching a spring past critical distances in a mass-spring system? Or perhaps swinging a pendulum from excessively large angles?
That's closer. In fact, if air friction is assumed proportional to speed, then it's an exact analog.So something like air friction while falling?
Right. But a pendulum in air would be considered damped, but not overdamped. So it would oscillate back and forth, with the amplitude of each swing getting smaller and smaller. This would be considered underdamped. An overdamped pendulum is when the friction is so large that it doesn't oscillate at all, but slowly swings back to it's equilibrium position. There is another possibility, called critically damped, in which the damping is just right so that the pendulum settles into its equilibrium position as quickly as possible.So something like air friction while falling?
The current would exponentially approach zero without reversing direction if damping is critical or higher.So if I understand this right, an overdamped circuit would discharge it's capacitor, and then settle down to have no current, as opposed to the capacitor and inductor working to keep a steady current? And all of this would be caused by a high amount of resistance (literal resistance, from a resistor)?