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Darboux integral

  1. Jul 13, 2006 #1
    if a function f is not integrable does it imply, that there exists such an epsilon that whichever partition P i choose it will follow this condition
    Last edited: Jul 13, 2006
  2. jcsd
  3. Jul 13, 2006 #2
    Looks ok yea, f:[a,b]->R not integrable implies there exists an e > 0 such that for all partitions P of [a,b], U - L >= e.
    Last edited: Jul 13, 2006
  4. Jul 13, 2006 #3
    Thank you.
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