- #1
physea
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Homework Statement
There is a tap that supplies water to a L=21m hose. There are friction losses in the hose due to friction (Darcy losses).
f = 0.0138
ρ = 1000 kg/m3
diameter d= 0.025m
water velocity V=2.54m/s
What is the pressure at the tap?
Homework Equations
Darcy losses: h= 4fLV^2/d2g
The Attempt at a Solution
My solution says that the pressure energy in the tap will have to maintain a flow of 2.54m/s and overcome the Darcy losses.
Darcy pressure losses are h=4fLV^2/d2g, and since P=ρgh, we get P(darcy)=4fLgV^2/2d
As a result P(tap)=V^2/2g + 4fLgV^2/2d = 486Pa
But it doesn't seem correct, any idea?
Apparently, the correct solutions says P=ρgh(darcy)